Formula 1:
S.I = P * R * N / 100
and A = S.I + P
Where,
P= principal amount
R= rate of interest
N= number of years &
A= amount
Formula 2:
A = P * ( 1 + R / 100n ) ^ nt
A = amount
P = principal
R = rate of interest
n = how the interest is compounded
e.g. n=1…when interest is compounded yearly
n=2… interest is compounded half yearly
n=4… interest is compounded quarterly
n=12… interest is compounded monthly
Exercise:-
1) What will
be the amount on Rs. 6400 for three years at the rate of interest 5% per annum ?
Solution:- here A=? , P=640 , R=5%
and N=3
S.I=P*R*N/100
S.I=6400*5*3/100
S.I=960
A=960+6400=7360
2) A sum of
money amount to Rs. 5017 in 2 years at the rate of 8% per annum, what was the
sum invested?
Solution:- here P=? , A=4500 , N=2
, R=8%
A=S.I+P=[P*R*N/100]+P
5017=[P*8*2/100]+P
5017=[4P/25]+P è 5017*25=29P èP=4325
3) Find the
time in which Rs. 5000 amount to Rs. 7000 at the rate of 2% p.a.
Solution:- here N=? , P=5000 ,
A=7000 , R=2%
A=S.I+P è S.I=2000
P*R*N/100=2000
5000*2*N=2000*100
N=20 years
4) What would
be the rate of interest when the sum of Rs. 6200 amount to Rs. 7440 in 5 years.
Solution:- here R=? , P=6200 ,
A=7440 , N=5
A=P+S.I è S.I=1240
P*R*N/100=1240
6200*R*5=1240*100
R= 4%
5) Find the
amount when the sum of Rs. 20,000 is compounded half yearly at the rate of 5%
p.a for 1 year.
Solution:- here A=? , P=20,000 ,
R=5% , n=2 , t=1
A = P * ( 1 + R / 100n ) ^ nt
A = 20,000 ( 1 + 5/100 ) ^ 2
A = 20,000 ( 21 / 20 ) ^2
A = 20,000 * 441/400 = 22050
No comments:
Post a Comment